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X^2-8X=134
We move all terms to the left:
X^2-8X-(134)=0
a = 1; b = -8; c = -134;
Δ = b2-4ac
Δ = -82-4·1·(-134)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-10\sqrt{6}}{2*1}=\frac{8-10\sqrt{6}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+10\sqrt{6}}{2*1}=\frac{8+10\sqrt{6}}{2} $
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